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Question

Find the sum of the following AP 1,3,5,7.............199

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Solution

AP is 1,3,5,7....199
a=1,d=2 and last term l=199
tn=a+(n1)d199=1+(n1)×22n=200n=100sum=n2[a+l]=1002[1+199]=1002×200=10000

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