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Standard X

Mathematics

Formula for Sum of n Terms of an AP

Find the sum ...

Question

Find the sum of the following APs: $0.6, 1.7, 2.8, . . . . . .$ to $100$ terms

5475

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5505

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6589

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3844

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Solution

The correct option is B 5505
Here $a = 0.6, d = 1.1$ and $n = 100$
As we know, $S_{n} = \frac{n}{2} [2 a + (n - 1) d]$
$∴ S_{100} = \frac{100}{2} (2 (0.6) + 1.1 \times 99) = 50 \times 110.1 = 5505$

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Find the sum of the following APs: 0.6,1.7,2.8,...... to 100 terms

The correct option is B 5505Here a=0.6,d=1.1 and n=100As we know, Sn=n2[2a+(n−1)d]∴S100=1002(2(0.6)+1.1×99)=50×110.1=5505

Find the sum of the following APs: $0.6, 1.7, 2.8, . . . . . .$ to $100$ terms

The correct option is B 5505
Here $a = 0.6, d = 1.1$ and $n = 100$
As we know, $S_{n} = \frac{n}{2} [2 a + (n - 1) d]$
$∴ S_{100} = \frac{100}{2} (2 (0.6) + 1.1 \times 99) = 50 \times 110.1 = 5505$