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Question

Find the sum of the following APs:
(i) 2, 7 ,12,....to 10 terms.
(ii) 0.6, 1.7 ,2.8,....to 100 terms.

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Solution

i)
2,7,1210 terms
a=2,d=5,n=10
Sn=n2[2a+(n1)d]
S10=102[4+9(5)]=245
ii)
0.6,1.7,2.8 100 terms.
a=0.6,d=1.1,n=100
S100=1002[2(0.6)+99(1.1)]=5505

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