Find the sum of the following harmonic series: 12+14+16+...10 terms.
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Solution
We know the formula for sum of nth term in arithmetic progression. The reciprocal of arithmetic progression is harmonic progression. a=2,d=2 Sn=n2[2a1+(n−1)d] S10=102[2×2+(10−1)2] S10=5[4+18] S10=110 Sum of first 10 terms of HP =1110