Find the sum of the following- 1- 1 n - 1- 2 n - 1- 3 n - upto n terms-

S =(1 1n)+(1 2n)+(1 3n)+— upto 'n' terms = (1+1+—n+times) 1n(1+2+3+–n term) = n 1n×n(n+1)2 = n n+12 = 2n n 12 = n 12 ...

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Collinearity Condition

Find the sum ...

Question

Find the sum of the following:
$(1 - \frac{1}{n}) + (1 - \frac{2}{n}) + (1 - \frac{3}{n}) + . . . .$ upto $n$ terms.

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