Find the sum of the following polynomials
$y^{2} + 2 y - 5; y^{3} + 2 y^{2} + 3 y + 4; y^{3} + 7 y - 2$

2 y^{3} + 3 y^{2} - 3

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2 y^{3} + 12 y - 3

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2 y^{2} + 3 y^{3} + 12 y - 3

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2 y^{3} + 3 y^{2} + 12 y - 3

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Solution

The correct option is D $2 y^{3} + 3 y^{2} + 12 y - 3$
$(y^{2} + 2 y - 5) + (y^{3} + 2 y^{2} + 3 y + 4) + (y^{3} + 7 y - 2)$

$= y^{2} + 2 y - 5 + y^{3} + 2 y^{2} + 3 y + 4 + y^{3} + 7 y - 2$
$= 2 y^{3} + 3 y^{2} + 12 y - 3$

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Similar questions

Divide the given polynomial by the given monomial:
$(2 y^{3} + 3 y^{2} + 12 y) \div 3 y$

4 \sqrt{2} y^{3}

3 \sqrt{2} y^{2}

({2 y}^{3} + {4 y}^{2} + 3) \div {2 y}^{2}

2 y^{3} + y^{3} - 2 y - 1

\frac{2 x}{3} + \frac{3 y}{2} = 8 \frac{1}{3}; \frac{3 x}{12} + \frac{2 y}{3} = 13 \frac{1}{3}

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