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Question

Find the sum of the following series.
1+(1+a)+r+(1+a+a2)r2+.... to (|r|<1).

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Solution

S=1+(1+a)r+(1+a+a2)r2+.......
arS=ar+(a+a2)r2+(a+a2+a3)r3+.......
(1ar)S=1+r+r2+r3+......
(1ar)S=11r
S=1(1r)(1ar)

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