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Question

Find the sum of the following series 11.2.3+13.4.5+15.6.7+....

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Solution

un=1(2n1).12n.1(2n+1)
=12{12n12n+12n+1}
2S=(1122+13)+(1324+15)+(1526+17)+......
1+2S=2(112+1314+1516+....)
1+2S=2loge2
2S=loge4logee
S=12loge4e

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