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Byju's Answer
Standard XII
Mathematics
Sigma n2
Find the sum ...
Question
Find the sum of the following series up to
n
terms:
5
+
55
+
555
+
.
.
.
.6
+
.66
+
.666
+
.
.
.
Open in App
Solution
S
n
′
=
5
+
55
+
555
+
.
.
.
.
n
t
e
r
m
s
=
5
(
1
+
11
+
111
+
.
.
.
.
.
.
.
n
t
e
r
m
s
)
=
5
9
[
9
+
99
+
999
+
.
.
.
.
.
n
t
e
r
m
s
]
=
5
9
[
(
10
−
1
)
+
(
100
−
1
)
+
(
1000
−
1
)
+
.
.
.
.
.
n
t
e
r
m
s
]
=
5
9
[
10
+
10
2
+
10
3
+
.
.
.
.
n
t
e
r
m
s
−
n
]
=
5
9
[
10
(
10
n
−
1
)
10
−
1
−
n
]
=
5
9
[
10
9
(
10
n
−
1
)
−
n
]
S
n
′
=
0.6
+
0.66
+
0.666
+
.
.
.
.
.
n
t
e
r
m
s
=
6
10
+
66
100
+
666
1000
+
.
.
.
.
.
.
.
.
n
t
e
r
m
s
=
6
10
[
1
+
11
10
+
111
100
+
.
.
.
.
n
t
e
r
m
s
]
=
6
90
[
9
+
99
10
+
999
100
+
999
100
+
.
.
.
.
n
t
e
r
m
s
]
Suggest Corrections
1
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