Question

Find the sum of the four digits number that can be formed with the digits $0,1,2$ and $3$.

Answer 1

Sum of numbers at the first place (1000's place)

$=6(1+2+3)=6\left(6\right)=36$

Sum of numbers at the first place (100's place)

$=6\left(0\right)+4(1+2+3)=4\left(6\right)=24$

Sum of numbers at the first place (10's place)

$=6\left(0\right)+4(1+2+3)=4\left(6\right)=24$

Sum of numbers at the first place (1's place)

$=6\left(0\right)+4(1+2+3)=4\left(6\right)=24$

Sum of all 4 digit numbers formed using 0 1 2 3

$36\times 1000=36000$

$24\times 100=2400$

$24\times 10=240$

$24\times 1=24$

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Total$=38664$