Question

Find the sum of the interior angles of a nonagon.

Answer 1

A polygon that has nine sides are known as nonagon.

$Angles\text{'}sum=(N-2)\times 180°$

Here, the total edges of the given polygon are$N=9.$

$$\begin{gathered} Anglessum=(9-2)\times 180° \\ Anglessum=1260° \end{gathered}$$

Therefore, the required sum is $1260°$.