Find the sum of the interior angles of an octagon.

180°

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540°

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900°

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1080°

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Solution

The correct option is D
1080°

Interior angle = (n-2) $\times$ 180 $^{\circ}$

Where n is the number of sides in a polygon.

Interior angle = (n-2) $\times$ 180 $^{\circ}$ (Octagon has 8 sides)

= 6 $\times$ 180 $^{\circ}$ = 1080 $^{\circ}$

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Find the sum of the interior angles of an octagon.

The correct option is D 1080° Interior angle = (n-2) × 180∘ Where n is the number of sides in a polygon. Interior angle = (n-2) × 180∘ (Octagon has 8 sides) = 6 × 180∘ = 1080∘

The correct option is D
1080°

Interior angle = (n-2) $\times$ 180 $^{\circ}$

Where n is the number of sides in a polygon.

Interior angle = (n-2) $\times$ 180 $^{\circ}$ (Octagon has 8 sides)

= 6 $\times$ 180 $^{\circ}$ = 1080 $^{\circ}$