Question

Find the sum of the lengths of the bases trapezium whose area is 4.2 $m^2$ and whose height is 280 cm.

Answer 1

Area of trapezium= 4.2 $m^2$

Height (h)=280 cm =2.8 m

$\therefore Sumofbases=\frac{Area\times 2}{Height}=\frac{4.2\times 2}{2.8}m=\frac{42\times 2\times 10}{10\times 28}=3m$