Question

Find the sum of the place values of two odd digits in 6,34,568.

Answer 1

We can observe that, odd digits in the given number are $3$ and $5$.

Place value of $3$ is $3\times 10000=30000$.

Place value of $5$ is $5\times 100=500$.

So, the sum of both the place values will be $30000+500=30500$.

Hence, the sum is $\mathbf{30500}$.