Find the sum of the products of the corresponding terms of the sequence $16, 32$ and $128, 32, 8, 2, \frac{1}{2}$

Open in App

Solution

Corresponding terms are $64$ and $\frac{1}{8}$
Sum $= 64 + \frac{1}{8} = \frac{5 / 3}{8}$
Product $= 64 \times \frac{1}{8} = 8$

Suggest Corrections

Similar questions

Find the sum of the products of the corresponding terms of the sequences 2, 4, 8, 16, 32 and 128, 32, 8, 2, .

Find the sum of the products of the corresponding terms of finite geometrical progressions

2, 4, 8, 16, 32 and 128, 32, 8, 2, $\frac{1}{2}$

Find the sum of the product of the corresponding terms of the sequences 2, 4 ,16 and 32 128, 32, 8 ,2 $\frac{1}{2}$ .

Q. Show that the products of the corresponding terms of the sequences form a G.P, and find the common ratio.

Show that the products of the corresponding terms of the sequences $a, a r, a r^{2}, . . . . . . . a r^{n - 1} a n d A, A R, A R^{2}, . . . . A R^{n - 1}$ form a G.P and find the common ratio.

Join BYJU'S Learning Program

Find the sum of the products of the corresponding terms of the sequence 16,32 and 128,32,8,2,12

Corresponding terms are 64 and 18Sum=64+18=5/38Product=64×18=8

Find the sum of the products of the corresponding terms of the sequence $16, 32$ and $128, 32, 8, 2, \frac{1}{2}$

Corresponding terms are $64$ and $\frac{1}{8}$
Sum $= 64 + \frac{1}{8} = \frac{5 / 3}{8}$
Product $= 64 \times \frac{1}{8} = 8$