Question

Find the sum of the roots of equation $(2x-1)(\frac{3x}{2}+1)=0$

• A. $\frac{1}{6}$
• B. $\frac{-1}{6}$
• C. $\frac{-1}{3}$
• D. $\frac{-1}{2}$

Answer 1

Answer: (B)

$\frac{-1}{6}$

Using zero product rule for the equation:
$(2x-1)(\frac{3x}{2}+1)=0$
$2x-1=0$, $(\frac{3x}{2}+1)=0$
$2x=1$

$x=$ $\frac{1}{2}$, $x=\frac{-2}{3}$
The sum of the roots $=$ $\frac{1}{2}-\frac{2}{3}$$=$ $\frac{-1}{6}$