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Question

Find the sum of the roots of the equation 2333x2+2111x+1=2222x+2+1

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Solution

let 2111x=y
equation becomes
y322+2y=22y2+1
y3+8y=16y2+1
y316y2+8y1=0
y1y2y3=2111(x1+x2+x3)
x1+x2+x3=log(y1y2y3)111log(2)
y1y2y3=1
x1+x2+x3=log1111log2
=0

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