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Question

Find the sum of the series : 3 + 5 + 7 + 6 + 9 + 12 + 9 + 13 + 17 + .... to 3n terms.

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Solution

In the given series 3 + 5 + 7 + 9 + .... to 3n.
Here,
a = 3
d = 2
Number of terms = 3n
The sum of n term is
Sn=n2[2a+(n1)d]S3n=3n2[6+(3n1)2]=3n(2n+3)


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