Find the sum of the series 3.nC0−8.nC1+13.nC2−18.nC3+…+(n+1)terms
A
0
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B
−1
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C
+1
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D
None of these
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Solution
The correct option is D0 Let n=2 Hence the above expression is reduced to 3(1)−8(2)+13(1) =16−16=0 Let n=3 3(1)−8(3)+13(3)−18(1) =42−42=0 Hence the sum of the series for n>1 is 0