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Byju's Answer
Standard XII
Mathematics
Sigma n2
Find the sum ...
Question
Find the sum of the series
3
×
8
+
6
×
11
+
9
×
14
+
.
.
.
.
to n terms.
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Solution
3
×
8
+
6
×
11
+
9
×
14
+
.
.
.
.
.
.
.
.
.
.
By observation, the first & second parts of
each term form an A.P
The
n
t
h
term would be
⇒
(
3
n
)
×
(
3
n
+
5
)
∑
n
n
=
1
(
3
n
)
(
3
n
+
5
)
⇒
∑
n
n
=
1
9
n
2
+
15
n
⇒
9
∑
n
n
=
1
n
2
+
15
∑
n
n
=
1
n
⇒
9
n
(
n
+
1
)
(
2
n
+
1
)
6
+
15
n
(
n
+
1
)
2
⇒
3
n
(
n
+
1
)
[
2
n
+
1
+
5
]
2
3
n
(
n
+
1
)
(
2
n
+
6
)
2
=
3
n
(
n
+
1
)
(
n
+
3
)
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