Find the sum of the serie 1-22-1-1-42-1-1-62-1-1-202-1

The correct option is D 10/21Option (C) is the correct answer. Check the video for the approach. ...

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Question

Find the sum of the series :
$\frac{1}{2^{2} - 1} + \frac{1}{4^{2} - 1} + \frac{1}{6^{2} - 1} + . . . . + \frac{1}{20^{2} - 1}$

\frac{8}{21}

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\frac{9}{21}

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\frac{10}{21}

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\frac{12}{21}

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\frac{1}{2^{2} - 1} + \frac{1}{(4^{2} - 1)} + \frac{1}{6^{2} - 1} + . . . . . + \frac{1}{20^{2} - 1}

(\frac{1}{2^{2} - 1}) + (\frac{1}{4^{2} - 1}) + (\frac{1}{6^{2} - 1}) + . . . + (\frac{1}{20^{2} - 1})

(\frac{1}{2^{2} - 1}) + (\frac{1}{4^{2} - 1}) + (\frac{1}{6^{2} - 1}) + (\frac{1}{20^{2} - 1})

[\frac{1}{(2^{2} - 1)}] + [\frac{1}{(4^{2} - 1)}] + [\frac{1}{(6^{2} - 1)}] + . . . + [\frac{1}{(20^{2} - 1)}]

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