Find the sum of the series 1-4 - 7-1-7 - 10-1-10 - 13-1-25 - 28-

The correct option is B 1/14 We can rewrite the given series in the form : (1/3)[(1/4 1/7)+(1/7 1/10)+(1/10 1/13)+........+(1/25 1/28)] Therefore, sum of the ...

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Quantitative Aptitude

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Find the sum ...

Question

Find the sum of the series $\frac{1}{4 \times 7} + \frac{1}{7 \times 10} + \frac{1}{10 \times 13} + . . . . + \frac{1}{25 \times 28} .$

6/28

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1/14

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3/28

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1/28

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Solution

The correct option is B
1/14

We can rewrite the given series in the form : $(\frac{1}{3}) [(\frac{1}{4} - \frac{1}{7}) + (\frac{1}{7} - \frac{1}{10}) + (\frac{1}{10} - \frac{1}{13}) + . . . . . . . . + (\frac{1}{25} - \frac{1}{28})]$

Therefore, sum of the series, $S = (\frac{1}{3}) (\frac{1}{4} - \frac{1}{28}) = (\frac{1}{3}) \times (\frac{6}{28}) = \frac{1}{14} .$

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Find the sum of the series 14×7+17×10+110×13+....+125×28.

The correct option is B 1/14 We can rewrite the given series in the form : (13)[(14−17)+(17−110)+(110−113)+........+(125−128)] Therefore, sum of the series, S=(13)(14−128)=(13)×(628)=114.

Find the sum of the series $\frac{1}{4 \times 7} + \frac{1}{7 \times 10} + \frac{1}{10 \times 13} + . . . . + \frac{1}{25 \times 28} .$