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Question

Find the sum of the series N=13+115+135.........100 terms


A
99199
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B
1199
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C
100201
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D
1201
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E
1199
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Solution

The correct option is C 100201
First term of the series (13)=1(3×1)=12[113]
Second term of the series (115)=1(3×5)=12[1315]
Third term of the series (135)=1(7×5)=12[1517]
..............................................................................
100th term of the series (1199×201)=12[11991201]
12[113+1315+1517+17...................+11991201]
12[11201]=200(2×201)=100201

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