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Question

Find the sum of the squares of the roots of the equation ∣ ∣ ∣3x2x2+xcosθ+cos2θx2+xsinθ+sin2θx2+xcosθ+cos2θ3cos2θ1+sin2θ2x2+xsinθ+sin2θ1+sin2θ23sin2θ∣ ∣ ∣=0 are ............

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Solution

Given equation is ∣ ∣ ∣3x2x2+xcosθ+cos2θx2+xsinθ+sin2θx2+xcosθ+cos2θ3cos2θ1+sin2θ2x2+xsinθ+sin2θ1+sin2θ23sin2θ∣ ∣ ∣=0
if x=cosθ equation becomes
∣ ∣ ∣3cos2θ3cos2θ1+sinθcosθ3cos2θ3cos2θ1+sinθcosθ1+sinθcosθ1+sinθcosθ3sin2θ∣ ∣ ∣=0
as C1 and C2 are identical.
if x=sinθ equation becomes

∣ ∣ ∣3sin2θ1+sinθcosθ3sin2θ1+sinθcosθ3cos2θ1+sinθcosθ3sin2θ1+sinθcosθ3sin2θ∣ ∣ ∣=0
as C1 and C3 are identical.
x=sinθ and x=cosθ are roots of the given eqaution.
Sum of squares of roots =sin2θ+cos2θ=1


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