Find the sum of the x-coordinates of the intersection of x^2 + y^2 = 36 and x^2 - y^2 = 6.
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Solution
The given equations are, x²+y²=36 -----------(1) x²-y²=6 --------------(2) For the intersection of these curves Adding (1) and (2) we get, 2x²=42 or, x=⁺₋√21 ∴, The sum of the x-coordinates is: √21+(-√21)=0