Find the sum of two consecutive numbers for $(15)^{2}$ .

112 and 113

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

113 and 114

No worries! We‘ve got your back. Try BYJU‘S free classes today!

115 and 112

No worries! We‘ve got your back. Try BYJU‘S free classes today!

113 and 115

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 112 and 113
$15^{2}$ $=$ $(10 + 5)^{2}$ $=$ $100 + 25 + 100$
$= 225$ $=$ $112 + 113$
Hence, option A is correct.

Suggest Corrections

Similar questions

The sum of three consecutive natural numbers is $114$ . Find the numbers.

Q. Find the sum of two consecutive number for

(13)^{2}

Q. Express the following as the sum of two consecutive positive integers.

15^{2}

ii)

21^{2}

11^{2} - 1

is a product of two consecutive even numbers. Find those two even numbers.

If twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178 and thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177, then find the smallest even number.

Join BYJU'S Learning Program

Find the sum of two consecutive numbers for (15)2.

The correct option is A 112 and 113152 = (10+5)2 = 100+25+100=225 = 112+113Hence, option A is correct.

Find the sum of two consecutive numbers for $(15)^{2}$ .

The correct option is A 112 and 113
$15^{2}$ $=$ $(10 + 5)^{2}$ $=$ $100 + 25 + 100$
$= 225$ $=$ $112 + 113$
Hence, option A is correct.