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Question

Find the sum of:
(v) 5x22xy+3y2,2x2+5xy+9y2 and 3x2xy4y2

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Solution

Step: Find the sum of given expressions
We need to find sum of (5x22xy+3y2), (2x2+5xy+9y2) and (3x2xy4y2) =(5x22xy+3y2)+(2x2+5xy+9y2)+(3x2xy4y2) =(5x22x2+3x2)+(2xy+5xyxy)+(3y2+9y24y2) [Grouping like terms] =(3x2+3x2)+(3xyxy)+(12y24y2)
=6x2+2xy+8y2
Hence, the answer is=6x2+2xy+8y2.

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