1
Question
Find the sum of:
(xi) 4x3+2x2−x+1,2x3−5x2−3x+6,x2+8 and (5x3−7x).
(xi) 4x3+2x2−x+1,2x3−5x2−3x+6,x2+8 and (5x3−7x).
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Solution
Step: Finding the sum
We need to add (4x3+2x2−x+1),(2x3−5x2−3x+6),(x2+8) and (5x3−7x).
=(4x3+2x2−x+1)+(2x3−5x2−3x+6)+(x2+8)+(5x3−7x)
=(4x3+2x3+5x3)+(2x2−5x2+x2)+(−x−3x−7x)+(1+6+8) [Grouping like terms]
=(6x3+5x3)+(3x2−5x2)+(−4x−7x)+(7+8) =11x3−2x2−11x+15
Hence, the answer is 11x3−2x2−11x+15.
We need to add (4x3+2x2−x+1),(2x3−5x2−3x+6),(x2+8) and (5x3−7x).
=(4x3+2x2−x+1)+(2x3−5x2−3x+6)+(x2+8)+(5x3−7x)
=(4x3+2x3+5x3)+(2x2−5x2+x2)+(−x−3x−7x)+(1+6+8) [Grouping like terms]
=(6x3+5x3)+(3x2−5x2)+(−4x−7x)+(7+8) =11x3−2x2−11x+15
Hence, the answer is 11x3−2x2−11x+15.
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