Find the sum or difference-7-8-10-5 - 4-5 -10-5

Solving bracket first, hence solving powers(7.8×10^ 5) – (4.5 ×10^ 5)= (7.8× 1/10^5) – (4.5 ×1/10^5)= (7.8/10^5) – (4.5/10^5)= 0.000078 0.000045= 0.000033 ...

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Standard XI

Chemistry

Units and Dimensions

Find the sum ...

Question

Find the sum or difference.
$(7.8 \times 10^{- 5}) - (4.5 \times 10^{- 5})$

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Solution

Solving bracket first, hence solving powers
$(7.8 \times 10^{- 5}) - (4.5 \times 10^{- 5})$
= $(7.8$ $\times$ $\frac{1}{10^{5}}$ ) $- (4.5$ $\times$ $\frac{1}{10^{5}}$ )
= ( $\frac{7.8}{10^{5}}$ ) – ( $\frac{4.5}{10^{5}}$ )
= $0.000078 - 0.000045$
= $0.000033$

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Find the sum or difference.(7.8×10-5)–(4.5×10-5)

Solving bracket first, hence solving powers(7.8×10-5)–(4.5×10-5)= (7.8× 1105) –(4.5 ×1105)= (7.8105) – (4.5105)= 0.000078-0.000045= 0.000033

Find the sum or difference.
$(7.8 \times 10^{- 5}) - (4.5 \times 10^{- 5})$

Solving bracket first, hence solving powers
$(7.8 \times 10^{- 5}) - (4.5 \times 10^{- 5})$
= $(7.8$ $\times$ $\frac{1}{10^{5}}$ ) $- (4.5$ $\times$ $\frac{1}{10^{5}}$ )
= ( $\frac{7.8}{10^{5}}$ ) – ( $\frac{4.5}{10^{5}}$ )
= $0.000078 - 0.000045$
= $0.000033$