Question

Find the sum:-

$\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$11+{\displaystyle \raisebox{1ex}{$2$}\!\left/ \!\raisebox{-1ex}{$3$}\right.}$}\right.$

Answer 1

$\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$11+{\displaystyle \raisebox{1ex}{$2$}\!\left/ \!\raisebox{-1ex}{$3$}\right.}$}\right.$

step-1

Take the LCM of $11\&3$ we get

$33$

step-2

$$\begin{gathered} \raisebox{1ex}{$15+22$}\!\left/ \!\raisebox{-1ex}{$33$}\right. \\ =\raisebox{1ex}{$37$}\!\left/ \!\raisebox{-1ex}{$33$}\right. \end{gathered}$$