Find the sum to 100 terms of the series 1 + 4 + 7 + 5 + 13 + 6.........
8825
The given series can be taken as two AP's by simple rearrangement of numbers, such as
(1 + 7 + 13......) and (4 + 5 + 6.......).
Now, we can find the sum of 50 terms for each AP formed. So, for first AP
S1=502(2+49×6)=7400 and similarly,
S2=502(8+49×1)=1425
So, Sum of first 100 terms =7400+1425=8825