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Question

Find the sum to indicated number of terms in each of the geometric progressions in 7,21,37,..... n terms.

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Solution

Here a=7 and r=217=3

We konw that Sn=a(rn1)r1 when r > 1

Sn=7[(3)n1]31

= 731×3+13+1[(3)n21]

= 7(3+1)2[(3)n21]


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