Find the sum to indicated number of terms in each of the geometric progressions in √7,√21,3√7,..... n terms.
Here a=√7 and r=√21√7=√3
We konw that Sn=a(rn−1)r−1 when r > 1
Sn=√7[(√3)n−1]√3−1
= √7√3−1×√3+1√3+1[(3)n2−1]
= √7(√3+1)2[(3)n2−1]
Find the sum to indicated number of terms in each of the geometric progressions in Exercise 7 to 10: