Find the sum to n terms: 1^3 + (1^3 + 2^3)/2 + (1^3 + 2^3 + 3^3)/3

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\frac{1^{3}}{1} + \frac{1^{3} + 2^{3}}{1 + 3} + \frac{1^{3} + 2^{3} + 3^{3}}{1 + 3 + 5} + \dots

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\frac{1^{3}}{1} + \frac{1^{3} + 2^{2}}{2} + \frac{1^{3} + 2^{3} + 3^{3}}{3} + . . . . .

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