The k th term of A.P. is 5k+1.
Let a, d be the first term and common difference of the given A.P.
The formula to find the terms in an A.P. is given by,
T n =a+( n−1 )d
Substitute the values in the above expression.
T k =a+( k−1 )×d 5k+1=a+kd−d 5k+1=kd+( a−d )
Compare the coefficients on both the sides.
a−d=1 d=5
Solve the above expression to obtain the values of a and d.
d=5 a=6
The formula for the sum of n terms in A.P. is given by,
S n = n 2 [ 2a+( n−1 )d ]
Substitute the values of aand d, as 6and 5 in the above expression.
S n = n 2 [ 2×6+( n−1 )×5 ] S n = n 2 ( 12+5n−5 ) = n 2 ( 5n+7 )
Thus, the sum of n terms of A.P. is = n 2 ( 5n+7 ).