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Question

Find the sum to n terms of the series 3 × 8 + 6 × 11 + 9 × 14 +…

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Solution

The given series is 3 × 8 + 6 × 11 + 9 × 14 + …

an = (nth term of 3, 6, 9 …) × (nth term of 8, 11, 14, …)

= (3n) (3n + 5)

= 9n2 + 15n


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