Question

Find the sum to n terms of the series $\frac{3}{1^2\times 2^2}+\frac{5}{2^2\times 3^3}+\frac{7}{3^2\times 4^2}......$ is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

At n=1, we should get $\frac{3}{4}$ (this is the sum to 1 term of the series)

Option (a) gives $=\frac{2}{4}=\frac{1}{2}$

Option (b) gives $\frac{3}{4}$

Option (c) gives $\frac{3}{8}$

Option(d) gives 8

Answer= option b