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Question

Find the sum to the series 1.n+2(n1)+3(n2)+...+n.1

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Solution

Given series: 1.n+2(n1)+3(n2)+..+n.1
rth term =r(nr+1)
The given series is summation of r(nr+1) where r varies from 1 to n.
Sum=nr=1[(n+1)rr2]=(n+1)(n)(n+1)2n(n+1)(2n+1)6
Sum=n(n+1)2[n+12n+13]
Or, Sum=n(n+1)2[3n+32n13]
Sum=n(n+1)2[n+23]=n(n+1)(n+2)6Ans.


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