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Question

Find the sum:

(vi) 3x+4xyy2,xy4x+2y2 and 3y2xy+6x


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Solution

Step: Find the sum

By grouping the terms having the same literals and adding, we get,

(3x+4xyy2)+(xy4x+2y2)+(3y2xy+6x)

=3x+4xyy2+xy4x+2y2+3y2xy+6x

=(3x4x+6x)+(4xy+xyxy)+(y2+2y2+3y2)

=x(34+6)+xy(4+11)+y2(1+2+3)

=5x+4xy+4y2

Hence, the sum of given terms is 5x+4xy+4y2.


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