Question

Find the supplement angle of angle $600$.

Answer 1

Here $\theta ={600}^o$

So, $n=\left[\frac{\theta }{360}\right]=\left[\left(\frac{600}{360}\right)\right]=\left[1.67\right]=1$

Where $\left[x\right]$ is greater integer function for $x$.

Supplement angle $\alpha =\theta -2n\left(180\right)$

$={600}^o-\left(1\right)\left({360}^o\right)$

$={600}^o-{360}^o$

$\alpha ={240}^o$