Question

Find the surface area and the volume of a beach ball shown in the figure.

Answer 1

$\begin{array}{c}Here\\ height=diameter=42cm\\ so,radiuswillbehalfofit=21cm\\ \therefore r=21cm\\ Now,\\ Volumeofthebeachball=\frac{4}{3}\pi r^3\\ =\frac{4}{3}\times 3.14\times {\left(21\right)}^3\\ =38772.72c{m}^3\\ surfaceofthebeachball=4\pi r^2\\ =4\times 3.14\times {\left(21\right)}^2\\ =5538.96c{m}^2.\\ Hence,thevolumeofthebeachballis38772.72c{m}^{3}and\\ surfaceareais5538.96c{m}^2.\end{array}$