Find the surface area of a cube whose edge is
(i) 1.2 m (ii) 27 cm (iii) 3 cm (iv) 6 m (v) 2.1 m

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Solution

(i) Edge of the cube (a) = 1.2 m
$∴ S u r f a c e a r e a = 6 a^{2} = 6 \times (1.2)^{2} m^{2}$
= $6 \times 1.44 = 8.64 m^{2}$
(ii) Edge of cube (a) = 27 cm
$∴ S u r f a c e a r e a = 6 a^{2} = 6 \times (27)^{2} m^{2}$
= $6 \times 729 = 4374 m^{2}$
(iii) Edge of cube (a) = 3 cm
$∴ S u r f a c e a r e a = 6 a^{2} = 6 \times (3)^{2} m^{2}$
= $6 \times 9 c m^{2} = 54 c m^{2}$
(iv) Edge of cube (a) = 6 m
$∴ S u r f a c e a r e a = 6 a^{2} = 6 \times (6)^{2} m^{2}$
= $6 \times 6 \times 6 = 216 m^{2}$
(v) Edge of the cube (a) = 2.1 m
$∴ S u r f a c e a r e a = 6 a^{2} = 6 \times (2.1)^{2} m^{2}$
= $6 \times 4.41 = 26.46 m^{2}$

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