Question

Find the surface area of a cube whose edge is

$\left(v\right)$ $2.1m$

Answer 1

Given: Edge of cube$=2.1m$

We know that,

Surface area of cube $=6\times (\text{side}{)}^2$

$=6\times (2.1{)}^2$

$=6\times 4.41$

$=26.46m^2$

Hence, the surface area of cube is $26.46m^2.$