Question

Find the surface area of a cube whose volume is
(i) $343m^3$ (ii) $216d{m}^3$

Answer 1

(i) Volume of a cube = 343 $m^3$
= $\sqrt[3]{37\times 7\times 7}=\sqrt[3]{37^3}=7m$
$\therefore$ Surface area = $6a^2=6(7{)}^2{m}^2=6\times 49=294m^2$
(ii) Volume of a cube = 216 $d{m}^3$
= $\sqrt[3]{36\times 6\times 6}=\sqrt[3]{36^3}dm=6dm$
$\therefore$ Surface area = $6a^2=6(6{)}^{2}d{m}^2=6\times 36=216d{m}^2$