Question

Find the surface area of a sphere whose volume is $38808$ ${cm}^3$

Answer 1

Volume of the sphere $=38808c{m}^3$

We know that volume of the sphere $=\frac{4}{3}\pi r^3$

Therefore,

$\frac{4}{3}\pi r^3=38808$

$r^3=9261$

$r=21cm$

We know that the surface area of the sphere

$=4\pi r^2$

$=4\pi \times {21}^2$

$=5544c{m}^2$

Hence, this is the answer.