Question

Find the $T.S.A.$ of a cube, whose volume is $3\sqrt{3}{a}^3$ cubic units.

Answer 1

Given: The volume of a cube =$3\sqrt{3}{a}^3$

Let the edge of the cube be p.

So, $p^3=3\sqrt{3}{a}^3=(\sqrt{3}{)}^3{a}^3$

And, the edge of cube = $p=\sqrt{3a}$

$\therefore$ Total surface area of cube $=6\left({\sqrt{3}}^2\right)a^2=3\times 6a^2$

Total surface area of cube $=18a^2.$