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Ideal Gas Equation

Find the temp...

Question

Find the temperature at which volume and pressure of 28 gm nitrogen gas becomes $10 d m^{3}$ & 2.46 atm respectively. (Molar mass of nitrogen gas = $28 g / m o 1^{- 1}$ )

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Solution

Given that,

Molar mass of nitrogen, $W = 28 g$

Pressure is, $P = 2.46 a t m$

Volume, $V = 10 d m^{3} = 10 L$

From gas equation,

$P V = n R T$

$P V = \frac{w}{m} R T$

$T = \frac{P V m}{W R}$ $R = 0.0821 L a t m / K / m o l$

$T = \frac{2.46 \times 10 \times 28}{28 \times 0.0821}$

$T = 299.63 K$

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