Find the temperature at which we get the same reading on both Celsius and Fahrenheit scales.
A
40∘C
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B
−40∘C
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C
20∘C
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D
−20∘C
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Solution
The correct option is B−40∘C Let t be the required temperature on the Celsius scale. Then by using the relation between Celsius and Fahrenheit scales, t100=t−32180 ⇒180t−100t=−3200 ⇒80t=−3200 ∴t=−40∘C