Find the temperature (in K) at which 3 moles of SO2 will occupy a volume of 10L at a pressure of 15atm.
[ a=6.71atm litre2 mol−2; b=0.0564litre mol−1]
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Solution
van der Waal equation is: (P+an2V2)(V−nb)=nRT
Given: P=15atm V=10L, n=3, a=6.71atm litre2 mol−2 (15+6.71×9100)(10−3×0.0564)=3×0.082×T
on solving we get : T=624K