Find the tension T1 in the string. Assume all surfaces to be smooth.
A
3N
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B
6N
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C
2N
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D
4N
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Solution
The correct option is B6N The FBDs of the masses are as shown Let the direction of the acceleration be as shown
The force F applied on the system is F=9√2N So, the effective force that will cause the motion of the system is the horizontal component of the applied force i.e. FH=Fcos45∘=9√2×1√2=9N Hence, from FBDs we have T2=a..........(i) T1−T2=a............(ii) From eq (i) & (ii) we have T1=2a............(iii) Also, we have FH−T1=a⟹9−T1=a .....(iv) Thus, from eq (iii) & (iv) we have, 9=3a⟹a=3m/s2 Hence, T1=2a=6N
Alternate:
Net force acting in the horizontal direction =Fcos45∘=9√2×1√2=9N a=Supporting ForceTotal mass=93=3m/s2
From the FBD of the block we have, 9−T1=1.a 9−T1=1(3)⇒T1=6N