Question

Find the tenth term of $G.P.$ $5,25,125$

Answer 1

Given$,$ $G.P:5,25,\mathrm{125.......}$

$a=5$ $,$ $r=\frac{a_2}{a_1}$ $=\frac{25}{5}=5$ $n=10$

Therefore

$a_n=a+r^{n-1}$

$a_{10}=5\times {\left(5\right)}^{10-1}$

$=5\times 5^9$

$=5^{10}$